|
|
Post by Min on Jun 9, 2005 11:42:07 GMT 11
Can anyone rejog my memory? What are the calculations to work out the other two sides of a right angle triangle. I have all the angles, and the longest length of the triangle as a value. Can anyone help? It's been so long since I did this stuff.  Thanks! And yeah I know the drawing's a bit bodgy...I'm working on it! Take the known side as 765, not 695. |
|
Roland
Guildmember
Ashlings' Prankmonkey 
Healer's Guildleader[x=crazedturkey]
Posts: 1,622
|
Post by Roland on Jun 9, 2005 12:04:01 GMT 11
SOH CAH TOA
so Sin (angle)= Opposite/hypotenuse
Cos (angle) = adjacent/hypotenuse
tan (angle) = oppositie/adjacent
so if you go
Let x be the base (short side)
and y be the longer side
cos (66.0) = x/765cm
and solve for x that will give you the base of the triangle..
then you can use pythagorus
i.e 695(squared) = x(squared) times y (squared)
Hope that helps!!
|
|
|
|
Post by Min on Jun 9, 2005 12:35:26 GMT 11
THANK YOU!! ;D
*showers mentallydisturbedturkey in chocca and tim tams*
|
|
|
|
Post by Elspeth on Jun 9, 2005 12:40:22 GMT 11
Min, what are you doing work for? Shouldn't you be mucking about on Ober.net instead?  * gets back to work before anyone notices* |
|
|
|
Post by Min on Jun 9, 2005 13:13:18 GMT 11
LOL! Yes, but the beauty of being female is that we can quite efficiently multi-task ;D
|
|
Roland
Guildmember
Ashlings' Prankmonkey
Healer's Guildleader[x=crazedturkey]
Posts: 1,622
|
Post by Roland on Jun 9, 2005 14:41:42 GMT 11
Anytime my dear Min, anytime |
|
|
|
Post by Elspeth on Jun 9, 2005 18:12:05 GMT 11
LOL! Yes, but the beauty of being female is that we can quite efficiently multi-task ;D Hehe! So true. I feel rather odd if I don't have at least three windows open at any one time...  |
|
